The normal boiling point of bromine is 58.8°C, and its enthalpy of vaporization is 30.91 kJ/mol. What is the approximate vapor pressure of bromine at 10.0°C?

Answer : The vapor pressure of bromine at is 0.1448 atm.

Explanation :

The Clausius- Clapeyron equation is :

where,

= vapor pressure of bromine at = ?

= vapor pressure of propane at normal boiling point = 1 atm

= temperature of propane =

= normal boiling point of bromine =

= heat of vaporization = 30.91 kJ/mole = 30910 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

Hence, the vapor pressure of bromine at is 0.1448 atm.

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but