If there is 0.2 M glucose along with 0.15 M NaCl in solution, what is the osmolarity of this solution? If there is 0.2 M glucose along with 0.15 M NaCl in solution, what is the osmolarity of this solution? 1. 500 mOsm 2. 2.15 Osm 3. 350 mOsm 4. 2.30 Osm 5. 300 mOsm

Option 5. 300 mOsm

Explanation:

Osmolarity is the sum of the concentrations of all molecular species that are "swimming" in a solvent. In this case there are two species because the water dissociates sodium chloride in Na + and Cl-. Therefore for each NaCl we will have two independent molecules. Glucose does not dissociate, so osmolarity would not be affected.

NaCl →  Na⁺  +  Cl⁻

0.15 M we have 0.15 moles/L . 2 = 0.30 Osm

As we have a value of 0.30 Osm, if we convert it to mOsm

0.30 Osm . 1000 mOsm /  1Osm = 300 mOsm

the leaf is an organ of a typical plant, and the main functions are to complete photosynthesis and allow the plant to exchange gas, just like how we have the respiratory system. leaves have the stomata, which collects maintains co2 and o2 levels. this is necessary for cell metabolism. the leaf also collects sunlight using chloroplasts. succinctly, leaves own a pivotal role in sustaining plant life.

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