A 1.00-kg block of copper at 100°C is placed in an in- sulated calorimeter of negligible heat capacity containing 4.00 L of liquid water at 0.0°C. Find the entropy change of (a) the cop- per block, (b) the water, and (c) the universe.

the entropy change of the copper block = - 117.29 J/K

the entropy change of the water = 138.01 J/K

the entropy change of the universe = 20.72 J/K

Explanation:

For Copper block:

the mass of copper block = 1.00 kg

Temperature of block of copper = 100°C

= (100+273)K

= 373K

Standard Heat capacity for copper = 386 J/kg.K

For water:

We know our volume of liquid water to be = 4.00 L

At 0.0°C Density of liquid water  = 999.9 kg/m³

As such; we can determine the mass since :

∴ the mass of 4.00 L of liquid water at 0.0°C will be its density × volume.

= 999.9 kg/m³ ×

= 3.9996 kg

so, mass of liquid water = 3.9996 kg

Temperature of liquid water at 0.0°C = 273 K

Standard Heat Capacity of  liquid water = 4185.5 J/kg.K

Let's determine the equilibruium temperature between the copper and the liquid water. In order to do that; we have:

∴ the equilibrium temperature = 275.26 K

NOW, to determine the Entropy change of the copper block; we have:

The entropy change of the  water can also be calculated as:

The entropy change of the universe is the combination of both the entropy change of copper and water.

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.

the answer is symmetrical : )