Henry’s law is important in environmental chemistry, where it predicts the distribution of pollutants between water and the atmosphere. The hydrocarbon cyclopropane (C3H6) emitted in wastewater streams, for example, can pass into the air, where it is degraded by processes induced by light from the sun. The Henry’s law constant for cyclopropane in water at 25 °C is 4273 atm, when the following form of the law is used: Pcyclopropane = kcyclopropane Xcyclopropane Calculate the partial pressure of cyclopropane vapor in equilibrium with a solution of 1.84 g of cyclopropane per 1010 L of water. How many cyclopropane molecules are present in each cubic centimeter of vapor?

Explanation:

Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid

number of moles of cyclopropane = 1.84 g / 42.08 g/mol = 0.044 mol

number of mole of water =  1010000 g / 18.02 g/mol = 56048.83 mol

mole fraction of cyclopropane = mole of cyclopropane / ( mole of water + mole of cyclopropane) = 0.044 mol / 56048.87 = 7.85 × 10⁻⁷

P cyclopropane = k henry × mole fraction of cyclopropane = 4273 atm × 7.85 × 10⁻⁷ = 0.00335 atm

b) number of cyclopropane molecules present in each cubic centimeter = ( 0.044 mol / 1010) × 6.022 × 10 ²³ / 1000 cm³ = 2.623 × 10 ¹⁶ molecules in cm³

confused

confused             hewdejdnjnjsnd

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.