How many grams of Chromium Chloride III are needed to produce 75.0 of Silver Chloride?
CrCl3 + AgNO3 --> Cr(NO3) +AgCL

27.61g

Explanation:

First thing first, generate a balanced equation for the reaction as illustrated below:

CrCl3 + 3AgNO3 —> Cr(NO3)3 + 3AgCl

Next, we'll find the molar mass of CrCl3 and AgCl:

Molar Mass of CrCl3 = 52 + (3x35.5)

= 158.5g/mol

Molar Mass of AgCl = 108 + 35.5 = 143.5g/mol

But from the balanced equation, 3 mol of AgCl was produced. Therefore, the mass conc. of AgCl from the equation = 3 x 143.5 = 430.5g.

From the equation,

158.5g of CrCl3 produced 430.5g of AgCl.

Therefore, Xg of CrCl3 will produce 75g of AgCl i.e

Xg of CrCl3 = (158.5x75) / 430.5 =27.61g.

So, 27.61g of CrCl3 will produce 75g of AgCl

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.