100cm3 of oxygen pass through a porous plug is 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is? [O = 16, H = 1]

12.5secs

Explanation:

From the question, we obtained the following information:

t1(O2) = 50sec

M1(O2) = 16 x 2 = 32g/mol

M2(H2) = 2 x 1 = 2g/mol

t2 (H2) =?

t2/t1 = √(M2/M1)

t2/50 = √(2 / 32)

t2/50 = √(1 / 16)

t2/50 = 1 / 4

Cross multiply

t2 x 4 = 50 x 1

Divide both side by 4

t2 = 50 / 4

t2 = 12.5secs

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation: