A monatomic ideal gas in a rigid container is heated from 221 K to 285 K by adding 8130 J of heat. How many moles of gas are there in the container?

15.28 moles

Explanation:

E = nR(T2 - T1)

E is the heat added = 8130 J

R is the gas constant = 8.314 J/mol.K

T2 is the final temperature of the gas = 285 K

T1 is the initial temperature of the gas = 221 K

8130 = n×8.314(285 - 221)

n = 8130/8.314×64 = 8130/532.096 = 15.28 moles

odds are decent that your handwriting right now looks a little bit different than it did five years ago, and will look different again in five more. when i look back through my notebooks from middle school to now, i see a long, slow progression from meticulous and teeny letters to bigger, sloppier ones, plus a few side detours: sometime in high school, for example, i decided those loopy cursive lowercase f’s were just the coolest, adopting them as the lone rep for cursive in my otherwise all-print handwriting.

explanation:

c. 75.7

i think that is the right