A solution of HNO 3 is standardized by reaction with pure sodium carbonate. 2 H + + Na 2 CO 3 ⟶ 2 Na + + H 2 O + CO 2 A volume of 26.66 ± 0.06 mL of HNO 3 solution was required for complete reaction with 0.9479 ± 0.0007 g of Na 2 CO 3 , (FM 105.988 ± 0.001 g/mol ). Find the molarity of the HNO 3 solution and its absolute uncertainty. Note: Significant figures are graded for this problem. To avoid rounding errors, do not round your answers until the very end of your calculations.

Explanation:

The given reaction equation is as follows.

The greatest molarity will be calculated as follows

  =

        = 0.00070584 mol/ml

or,    = 0.70584 mol/L          (as 1 l = 1000 ml)

The smallest molarity will be calculated as follows.

       = 0.00070115 mol/ml

       = 0.70115 mol/l

Now, we will find the average as follows.

          = 0.703495

Now, half of the difference will be calculated as follows.

             = 0.002

therefore, we can conclude that the resulting answer is 0.703 ± 0.002 mol/L .

16

explanation:

the marks go by 4s