The boiling point elevation of an aqueous sucrose solution is foundto be 0.39 degrees celsius. What mass of sucrose (molar mass =342.30g/mol) is contained in 500.0g of the solution? Kb=0.512 degrees celsius/molality

A) 261 g sucrose
B)528 g sucrose
C)130 g sucrose
D)762g sucrose
E)223g sucrose

The mass of sucrose is 130 grams (option C)

Explanation:

Step 1: Data given

The boiling point elevation of an aqueous sucrose solution is foundto be 0.39 °C.

Molar mass of sucrose = 342.30 g/mol

Mass of the solution = 500.0 grams

Kb=0.512 °C/molal

Step 2: Calculate molality

Tb = i*Kb*m

⇒ Tb = The boiling point elevation of an aqueous sucrose solution = 0.39 °C.

⇒ i = The van't Hoff factor = 1

⇒ Kb = 0.512 °C/ molal

⇒ m = the molality = moles sucrose / mass water

0.39 °C = 1*0.512 °C/molal* molality

Molality =0.76 molal

Step 3: Calculate moles sucrose

Molality = moles sucrose / mass water

0.76 molal = moles sucrose / 0.500 kg

moles sucrose = 0.38 moles

Step 4: Calculate mass sucrose

Mass sucrose = moles sucrose * molar mass sucrose

Mass sucrose = 0.38 moles * 342.30 g/mol

Mass sucrose = 130 grams

The mass of sucrose is 130 grams (option C)

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explanation:  

tariffs are a tax on anything that are imported from abroad. government use them to protect and boost their local industries and the thought is that they encourage consumers to buy local instead of importing and they will hope will protect jobs and economy in the country that implements them