A chemical company is considering replacing a batch reactor with a continuous reactor. The old unit cost $40,000 when new 5 years ago, and depreciation has been charged on a straightline basis using an estimated service life of 10 years with a final salvage value of $1000.The new unit would cost $70,000. It would save $15,000 per year in expenses not including depreciation. The straight-line depreciation period is taken to be 10 years with a zero salvage value. All costs other than those for labor, insurance, taxes, and depreciation may be assumed to be the same for both units. The old unit can now be sold for $5000. Income tax is 35 percent per year. If the after-tax minimum acceptable return on any investment is 15 percent, should the replacement be made?

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

i'm assuming that the correct answer is indeed the first one/ "a"..

yes

ya te ayud espera