The reaction A + 2B → products has been found to have the rate law, rate = k[A][B]2. While holding the concentration of A constant, the concentration of B is tripled. Predict by what factor the rate of reaction increases

9 times

Explanation:

A + 2B → products

rate = k[A][B]2

While holding the concentration of A constant, the concentration of B is tripled. Predict by what factor the rate of reaction increases.

We can achieve this by given the concentration dummy values.

Assuming the following values (Any number works, or letters);

concentration of A = 1

Concentration of B = 2

rate = k[A][B]2

rate = k (1)* (2)^2

rate = k 4 i

When Conc of B is tripled;

Concentration of B = 3 * 2 = 6

rate = k[A][B]2

rate = k (1) * (6)^2

rate = k 36 ii

Comparing both rates;

The ratio is 36: 4, upon simplifying = 9 : 1

This means the factor increases by 9 times

it takes on an electronical energy