A person pushes horizontally with a force of 220. N on a 56.0 kg crate to move it across a level floor. The coefficient of kinetic friction is 0.21. (a) What is the magnitude of the frictional force? (b) What is the magnitude of the crate's acceleration?

Explanation:

(a)   As it is given that there is no vertical displacement. Hence, the forces on y-axis are equal and opposite.

Also, it is known that F = mg

So,            F =

                    = 548.8 N

Also,  

where,   = coefficient of kinetic friction

                 N = force calculated

Putting the values into the formula as follows.

                       =

                      = 115.25 N

Hence, the magnitude of the frictional force is 115.25 N.

(b)   Now, let us assume that the acceleration is towards the positive x-direction.

                  a = 7.74

Therefore, the magnitude of the crate's acceleration is 7.74 .

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