The density at 20 ∘C of a 0.828 M solution of acetic acid in water is 1.0052 g/mL. The molar mass of acetic acid, CH3CO2H, is 60.05 g/mol. What is the molality of the solution?

Answer : The molality of solution is, 0.866 mole/kg

Explanation :

The relation between the molarity, molality and the density of the solution is,

where,

d = density of solution  = 1.0052 g/ml

m = molality of solution  = ?

M = molarity of solution  = 0.828 M = 0.828 mol/L

= molar mass of solute (acetic acid) = 60.05 g/mole

Now put all the given values in the above formula, we get  the molality of the solution.

Therefore, the molality of solution is, 0.866 mole/kg