What is the mole fraction of I2 in a solution made by dissolving 55.6 g of I2 in 245 g of hexane, C6H14?

The answer to your question is X = 0.072

Explanation:

Data

X I₂ = ?

mass of I₂ = 55.6 g

mass of hexane = 245 g

Formula

X I₂ = (moles of Iodine) / (moles of iodine + moles of hexane)

Process

1.- Convert the mass of reactants to moles

atomic mass of I₂ = 2 x 127 = 254g

atomic mass of hexane = (12 x 6) + (14 x 1) = 86 g

                      254 g 1 mol

                         55.6 g  x

                         x = (55.6 x 1)/254

                         x = 0.22  moles of I₂

                          86 g   1 mol

                         245 g   x

                          x = (245 x 1)/86

                          x = 2.84 moles

2.- Calculate the mole fraction of I₂

X = 0.22 / (0.22 + 2.84)

X = 0.22 / 3.07

X = 0.072