Of aluminum and is 1000µm long, 20nm wide, and 40nm thick, what would be the resistance of the interconnect?

Answer : The interconnect resistance will be, 35250 Ω

Explanation :

The formula used to calculate the interconnect resistance is:

where,

R = resistance = ?

L = length of wire = 1000 μm = 1000 × 10⁻⁶ m

T = thickness of wire = 40 nm = 40 × 10⁻⁹ m

W = width of wire = 20 nm = 20 × 10⁻⁹ m

= resistivity of aluminum = 2.82 × 10⁻⁸ Ωm

A = area

Now put all the given values in the above formula, we get:

Thus, the interconnect resistance will be, 35250 Ω

answer: c.

explanation:

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