If 2.0×10−4 moles of S2O2−8 in 170 mL of solution is consumed in 170 seconds , what is the rate of consumption of S2O2−8?

Answer : The rate of consumption of is,

Explanation : Given,

Moles of =

Volume of solution = 170 mL = 0.170 L     (1 L = 1000 mL)

Time = 170 s

First we have to calculate the concentration.

Now we have to calculate the rate of consumption.

Thus, the rate of consumption of is,

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