Nick and Kel reacted 2.80 g of NiCl2· 6 H2O with 7.00 mL of 4.00 M C2H8N2. They recovered 2.40 g of product, [Ni(C2H8N2)3] Cl2. At the end, the filtrate was a dark blue solution. The litmus test on the filtrate solution left the red litmus paper unchanged in color.

Actual Product yield = 0.028 x 308.7

Explanation:

Limiting reactant

moles of NiCl2.6H2O = 2.80 g/237.7 g/mol = 0.011 mol

moles of C2H8N2 = 4 M x 7.00 ml = 0.028 mol

for formation of complex,

If all of NiCl2.6H2O is consumed we would need = 0.011 x 3 =0.033 mols of C2H8N2

If all of C2H8N2 is consumed we reuire = 0.028/3 = 0.009 mols ofNiCl2.6H2O

since moles of NiCl2.6H2O available is in excess, C2H8N2 is limiting reactant

Actual Product yield = 0.028 x 308.7

sure what is it? ^w^

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.