Chemistry, 12.02.2020 06:01 baileybryant580
If Δ[NO]/ Δt = –20.0 M/s under a given set of conditions, what are the rates of change of [N2] and [H2O]?
Answers: 3
![[N_2]](/tpl/images/0508/3436/2c251.png)
= 10.0 M/s![[H_2O]](/tpl/images/0508/3436/b5d70.png)
= 20.0 M/s![\frac{d[NO]}{dt}](/tpl/images/0508/3436/925a1.png)
= 20.0 M/s
![\frac{-1}{2} \frac{d[NO]}{dt} = \frac{d[N_2]}{dt}](/tpl/images/0508/3436/7a5a8.png)
![\frac{-1}{2} (-20.0M/s)= \frac{d[N_2]}{dt}](/tpl/images/0508/3436/895eb.png)
![-1 *-10.0M/s= \frac{d[N_2]}{dt}](/tpl/images/0508/3436/5eb99.png)
![10.0M/s= \frac{d[N_2]}{dt}](/tpl/images/0508/3436/66fbb.png)
![\frac{d[N_2]}{dt}= 10.0M/s](/tpl/images/0508/3436/520de.png)
![\frac{-1}{2} \frac{d[NO]}{dt} = \frac{+1}{2} \frac{d[H_2O]}{dt}](/tpl/images/0508/3436/5df43.png)
![\frac{-1}{2} (-20.0M/s)= \frac{+1}{2} \frac{d[H_2O]}{dt}](/tpl/images/0508/3436/306de.png)
![10.0 M/s= \frac{+1}{2} \frac{d[H_2O]}{dt}](/tpl/images/0508/3436/87579.png)
![10.0 M/s*2= \frac{d[H_2O]}{dt}](/tpl/images/0508/3436/835a5.png)
![\frac{d[H_2O]}{dt} = 20.0 M/s](/tpl/images/0508/3436/c5476.png)
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If Δ[NO]/ Δt = –20.0 M/s under a given set of conditions, what are the rates of change of [N2] and [...
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