Acurrent of 9 a flows through an electric device with a resistance of 43 ω. what must be the applied voltage in this particular circuit?

The answer would be:

387 V

Just remember Ohm's Law:

V = IR

Where:

V = Voltage (V)

I = Current (A)

R = Resistance (Ω)

Our given is the following:

I = 9 A

R = 43 Ω

Now all you need to do is plug in all the values:

V = IR

V = (9A)(43Ω)

V = 387 V

indium, and thallium have three electrons i think

i believe it is c.) 1575 j.