An 85-g sample of iron is at an initial temperature of 38 °C. If 2213 joules of heat are applied to the sample, what is the final temperature of the iron?

The final temperature of the iron is 95.86 °C

Explanation:

To solve the question we must first find out the specific heat of iron which is 0.450 J/g°C

Then we list out the known variables

Initialtemperature = 38 °C

Applied heat = 2213 joules

Mass of sample = 85 g

Therefore, the required formula relating the final temperature of the iron to the known variables is

ΔH = m·C·Δθ where ΔH = applied heat, m = mass, C = specific heat capacity

plugging in the values we have

2213 J = 85 g×0.450 J/g° C× (T₂ - 38 °C), where T₂ = The final temperature of the iron

2213 J - 1453.5 J = 38.25 × T₂ or T₂ = 95.86 °C

The final temperature of the iron is 95.86 °C

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.