What is the percent yield for the reaction below when 544.5 g SO2 and 160.0 g O2 produce 382.0 g SO3? 2SO2(g) + O2(g) 2SO3(g)

h let me think

your answer is c) plasma

~*"auba14"*~

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol