A toy balloon filled with air has an internal pressure of 126.625 kPa and a volume of 2500 mL. If I take the balloon to the bottom of the ocean where the pressure is 95 atmospheres, what will the new volume of the balloon be in mL?

V2 = 337646.86 mL

Explanation:

Boyle's law:

assuming constant temperature and ideal gas:

V1P1 = V2P2

∴ V1 = 2500 mL

∴ P1 = 126.625 KPa

∴ P2 = (95 atm)×(0.009869 KPa/atm) = 0.9375 KPa

⇒ V2 = V1P1/P2

⇒ V2 = ((2500 mL)(126.625 KPa))/(0.9375 KPa)

⇒ V2 = 337646.86 mL

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.