In the following reaction, how many grams of lead(II) nitrate Pb(NO3), will produce 425 grams of sodium nitrate (NaNO3)?
Pb(NO3)2(aq) + 2 NaBr(aq) - PbBr2(s) +2 NaNO3(aq)
The molar mass of Pb(NO3)2 is 331.21 grams and that of NaNO3 is 85 grams.

Answer is: (A) 828.03 grams of lead(II) nitrate.

Balanced chemical reaction:

Pb(NO₃)₂(aq) + 2NaBr(aq) → PbBr₂(s) + 2NaNO₃(aq).

m(NaNO₃) = 425 g; mass of sodium nitrate.

M(NaNO₃) = 85 g/mol; molar mass of sodium nitrate.

n(NaNO₃) = m(NaNO₃) ÷ M(NaNO₃).

n(NaNO₃) = 425 g ÷ 85 g/mol.

n(NaNO₃) = 5 mol; amount of sodium nitrate.

From balanced chemical reaction: n(NaNO₃) : n(Pb(NO₃)₂) = 2 : 1.

n(Pb(NO₃)₂) = 5 mol ÷ 2.

n(Pb(NO₃)₂) = 2,5 mol; amount of lead(II) nitrate.

m(Pb(NO₃)₂) = n(Pb(NO₃)₂) · M(Pb(NO₃)₂)

m(Pb(NO₃)₂) = 2.5 mol · 331.21 g/mol.

m(Pb(NO₃)₂) = 828.03 g.

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this chemical reaction releases energy in the form of light and heat. chemical energy is the potential energy stored in the arrangement of atoms within molecules. breaking chemical bonds requires energy, while forming new chemical bonds releases energy.

the atp molecule can store energy in the form of a high energy phosphate bond joining the terminal phosphate group to the rest of the molecule. in this form,energy can be stored at one location, then moved from one part of the cell to another, where it can be released to drive other biochemical reactions.

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