The osmotic pressure, π, of a solution of glucose is 83.1 atm . find the molarity of the solution at 298 k. express the molarity to three significant figures and include the appropriate units.

Molarity for this solution is: 3.40 mol/L

Explanation:

Osmotic pressure is the colligative property which formula is:

π = M . R . T

83.1 atm = M . 0.082 L.atm/mol.K . 298K

83.1 atm / (0.082 L.atm/mol.K . 298K) = M

As you see all the units are cancelled, except for mol/L which means certainly Molarity

83.1 atm / (0.082 L.atm/mol.K . 298K) = 3.40 mol/L

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.