What is the overall cell potential for this redox reaction?

cl2 + ni = ni2+ + 2cl-
cl2 + 2e- = 2cl- 1.36 v
ni = ni2+ + 2e- -0.25 v

0.62 v
b.)0.61 v
c.)1.01 v
d.)1.61 v
e.)2.06 v

Oxid  # :     0          0                   +2        -1



∴ the nickel was oxidized while chlorine was reduced

nickel reduction potential =  - 0.25 V
              but since it is being oxidised the you have to switch the integer sign so the 
              the potential of nickel in this case becomes + 0.25 V

chlorine was reduced thus its reduction potential remains same  = + 1.36 V

Overall Cell potential  =  ∑ of half cell potential

The overall cell potential  =  (+ 1.36) + (+ 0.25)
                                         =   + 1.61 V

∴ the answer would be D

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