How many moles of sodium metal are needed to make 3.6 moles of sodium chloride? given the reaction: 2na + cl2 → 2nacl

3.6 moles of Na

Explanation:

Reaction is this one:

2Na + Cl₂ → 2NaCl

Ratio is 2:2, so 3.6 moles of NaCl could come from 3.6 moles of Na,

If we have to convert the mass to moles

3.6 mol . 23 g/mol = 82.8 g

3.6 moles

Explanation:

2Na + Cl2 → 2NaCl

From the balanced chemical equation above, we can tell that 2 mole of Sodium Metal reacts with 1 mole of Chlorine molecule to form 2 mole of sodium chloride.

How many moles would then form 3.6 moles of sodium chloride?

2 mol = 2 mol

x mol = 3.6 mol

Upon solving for x, we have;

x = (3.6 * 2) / 2

x = 3.6 mol

This means that 3.6 moles of sodium metal would be needed to make 3.6 moles of sodium chloride

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.