Calculate the volume in milliliters of a 2.09 m silver nitrate solution that contains 400 g of silver nitrate agno3. round your answer to 3 significant digits.

The volume is 1.13 *10³ mL

Explanation:

Step 1: Data given

Molarity of silvernitrate = 2.09 M

Mass of silvernitrate = 400 grams

Molar mass of silvernitrate = 169.87 g/mol

Step 2: Calculate number of moles

Number of moles = mass silvernitratre / molar mass silvernitrate

Number of moles = 400.0 grams / 169.87 g/mol

Number of moles =  2.355 moles

Step 3: Calculate volume

Molarity = moles / volume

Volume = moles / molarity

Volume = 2.355 moles / 2.09 M

Volume = 1.13 L = 1130 mL = 1.13 *10³ mL

The volume is 1.13 *10³ mL

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.