Calculate the volume in milliliters of a 1.1 m aluminum chloride solution that contains 125.0 g of aluminum chloride. round your answer to significant digits.

852 mL

Explanation:

Data of molarity means, moles of solute in 1L of solution

Let's convert the mass of solute, into moles

Mass / Molar mass = moles

125 g / 133.33 g/mol = 0.937 moles

In 1.1 moles of AlCl₃ are contained in 1L of solution

0.937 moles of AlCl₃ are contained in (0.937 mol . 1L) / 1.1 mol = 0.852L

Let's convert the L to mL

0.852L . 1000 mL/ 1L = 852 mL

The volume of solution is 8.5*10^2 mL

Explanation:

Step 1: Data given

Molarity of an aluminium chloride solution = 1.1 M

Mass of aluminium chloride = 125.0 grams

Molar mass of aluminium chloride = 133.34 g/mol

Step 2: Calculate moles AlCl3

Moles AlCl3 = mass AlCl3 / molar mass AlCl3

Moles AlCl3 = 125.0 grams / 133.34 g/mol

Moles AlCl3 = 0.9375 moles

Step 3: Calculate volume of the solution

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.9375 moles / 1.1 M

Volume = 0.852 L = 852 mL

Volume = 8.5 *10^2  mL

The volume of solution is 8.5*10^2 mL

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)