Consider this reaction:

2cl2o5 (g) → 2cl2 (g) + 5o2 (g)

at a certain temperature it obeys this rate law.
rate = (6.48 m-1 • s-1)[cl2o5]2
suppose a vessel contains cl2o5 at a concentration of 1.16 m. calculate the concentration of cl2o5 in the vessel 0.820 seconds later. you may assume no other reaction is important.
round your answer to 2 significant digits.

Answer : The concentration of in the vessel 0.820 seconds later is, 0.16 M

Explanation :

The given reaction is:

The rate law expression is:

The expression used for second order kinetics is:

where,

k = rate constant =

t = time = 0.820 s

= final concentration = ?

= initial concentration = 1.16 M

Now put all the given values in the above expression, we get:

Therefore, the concentration of in the vessel 0.820 seconds later is, 0.16 M

it would be d. henry moseley

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and sorry if i'm late. have a good rest of your day! : d

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