Achemist adds 380.0ml of a ×9.7510−4mm magnesium fluoride mgf2 solution to a reaction flask. calculate the micromoles of magnesium fluoride the chemist has added to the flask. round your answer to 3 significant digits.

0.370 micromoles of magnesium fluoride the chemist has added to the flask.

Explanation:

Moles of  magnesium fluoride  = n

Volume of the solution = 380.0 mL = 0.380 L (1 mL = 0.001 L)

Molarity of the solution =

(1 mM = 0.001 M)

1 mole = micro mole

0.370 micromoles of magnesium fluoride the chemist has added to the flask.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o