The infrared spectrum above represents the absorption of certain wavelengths of radiation by molecules of co2. which of the following best explains what occurs at the molecular level as the co2 molecules absorb photons of the infrared radiation?

Carbon Dioxide is an Infrared Radiation Absorber. The (CO2) molecules also emits the absorbed infrared (IR) radiation energy. The photon energy from the infrared radiation causes the CO2 molecule to vibrate. Only some of its vibrational modes absorb infrared radiation

Explanation:

Its linear structure is considered when working with the formula to calculate the number of molecular vibrational modes. It has 3n - 4 vibrational modes, where n is the number of atoms in a compound of CO2

With 3 atoms, CO2 has

3n−5=4 types or patterns of vibration

1. The symmetric stretch

2. The asymmetric stretch

3. The bend

The symmetric stretch vibrational mode is ir-inactive.

The asymmetric stretch is ir-active as it results in changes in dipole moment

The bend is ir-active as well as it results in a change in dipole moment too.

At the molecular level as the CO2 molecules absorb photons of the infrared radiation, the atoms in the CO2 molecules increase their vibration as the bonds between the atoms bend and stretch.

The question is incomplete, the complete question is;

The infrared spectrum above represents the absorption of certain wavelengths of radiation by molecules of CO2. Which of the following best explains what occurs at the molecular level as the CO2 molecules absorb photons of the infrared radiation?

The infrared spectrum of molecules is based on changes in the vibrational energy levels within the molecule.

Infrared radiation causes bonds to vibrate. The nature of the vibration may be stretching or bending.

So, when CO2  molecules are irradiated with infrared radiation, at the molecular level, CO2 molecules absorb photons of the infrared radiation, the atoms in the CO2 molecules increase their vibration as the bonds between the atoms bend and stretch.

Learn more: link

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole