By titration, 15.0 ml of 0.1008 m sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. what is the molar mass of the acid if it is monopro-tic

The molar mass of monoprotic acid is 135.9 g/mol

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of NaOH solution = 0.1008 M

Volume of solution = 15.0 mL

Putting values in above equation, we get:

As, the acid is monoprotic, it contains 1 hydrogen ion

1 mole of ion of NaOH neutralizes 1 mole of ion of monoprotic acid

So, 0.00151 moles of ion of NaOH will neutralize of ion of monoprotic acid

Moles of monoprotic acid = 0.00151 moles

To calculate the number of moles, we use the equation:

Moles of monoprotic acid = 0.00151 mole

Given mass of monoprotic acid = 0.2053 g

Putting values in above equation, we get:

Hence, the molar mass of monoprotic acid is 135.9 g/mol

answer: mercury

explanation:

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.