Part iv. for each trial, calculate the number moles of 6.0 m hcl used in the reaction. report your answer using 4 digits. note that it is 1 or 2 digits beyond the number of significant figures, i. e. 0.2345 moles.

This is an incomplete question, here is a complete question.

For each trial, calculate the number moles of 6.0 M HCl used in the reaction?

Trial 1 : Volume of HCl = 15.0ml

Trial 2 : Volume of HCl = 14.9ml

Trial 3 : Volume of HCl = 15.2ml

Answer :

The number moles of HCl for trial 1, 2 and 3 is, 0.090 mol, 0.089 mol and 0.091 mol

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

In this question, the solute is HCl.

Now we have to calculate the number of moles of HCl for trial 1.

Volume of HCl = 15.0 mL = 0.015 L

Now we have to calculate the number of moles of HCl for trial 2.

Volume of HCl = 14.9 mL = 0.0149 L

Now we have to calculate the number of moles of HCl for trial 3.

Volume of HCl = 15.2 mL = 0.0152 L

hloride, what is the mass of calcium in

explanation:

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.