Binary compound created by reaction of an unknown element e and sulfur contains 27.52% e and 72.48% s by mass. if the formula of the compound is e4s10, calculate the atomic mass of e.

Answer : The atomic mass of E is, 30.4 g/mol

Explanation :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of E = 27.52 g

Mass of S = 72.48 g

First we have to calculate the moles of sulfur.

Moles of S =

Now we have to calculate the moles of E by comparing the stoichiometry of the compound.

The given compound formula is,

As, 10 moles of sulfur combine with 4 moles of E

So, 2.265 moles of sulfur combine with moles of E

Thus, the moles of E is, 0.906 moles.

Now we have to calculate the atomic mass of E.

Atomic mass of E =

Thus, the atomic mass of E is, 30.4 g/mol

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

personal, she chose to do it.