Under what conditions does an increase in temperature turn a nonspontaneous process into a spontaneous process?

choose one or more:

a. δh < 0, δs > 0
b. δh > 0, δs > 0
c. δh > 0, δs < 0
d. δh < 0, δs < 0

(what i'm trying to figure out is if you need to consider t being negative or positive to start)

ΔH < 0, ΔS > 0

Explanation:

Consider ∆G= ∆H-T∆S

If ∆H is negative and and ∆S is positive, when T is increased, T∆S becomes more positive until the result of the difference between ∆H-T∆S becomes negative. Remember that a reaction is only spontaneous when ∆G is negative. Hence under these conditions, ∆G becomes negative and the reaction becomes spontaneous.

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.