Combustion reactions are exothermic. the heat of reaction for the combustion of cyclopropane, c3h6, is 499.8 kcal/mol. what is the heat of combustion for cyclopropane in kcal/gram?

Answer : The heat of combustion for cyclopropane in kcal/gram is, 5.95 kcal/g

Explanation : Given,

Heat of reaction for the combustion of cyclopropane = 499.8 kcal/mol

Molar mass of cyclopropane = 42 g/mol

The balanced chemical combustion reaction will be:

From the balanced chemical reaction we conclude that,

As, the heat of combustion of cyclopropane for 2 moles of cyclopropane = 499.8 kcal

And, the heat of combustion of cyclopropane for 1 mole of cyclopropane =

We know that:

To calculate the heat of combustion in per gram, we divide the given heat of combustion in kcal/mol by the molar mass of cyclopropane, we get:

Hence, the heat of combustion for cyclopropane in kcal/gram is, 5.95 kcal/g

explanation:

i think option no d is the correct answer

m=9

step-by-step explanation: