Calculate the solubility of oxygen in water at 25c when the total external pressure is 1 at and the mole fractionof oxygen in the air is 0.2

The given question is incomplete. The complete question is as follows.

The value of Henry's law constant for oxygen in water at is M/torr.

Calculate the solubility of oxygen in water at when the total external pressure is 1 atm and the mole fraction of oxygen in the air is 0.20 atm.

Explanation:

Formula to calculate partial pressure of a gas is as follows.

   Partial pressure of oxygen = mole fraction of oxygen x total pressure

Putting the given values into the above equation as follows.

       = = 152 torr

Therefore, solubilty (concentration) of oxygen in water  will be calculated as follows.

        Solubility = Henry's law constant x partial pressure of oxygen

                       =

                       = M

Thus, we can conclude that solubility of given oxygen is M.