Hcl(aq)+naoh(aq)→nacl(aq)+h2o(l)δh° =−57.1kj/molrxn
the chemical equation above represents the reaction between hcl(aq) and naoh(aq). when equal volumes of 1.00mhcl(aq) and 1.00mnaoh(aq) are mixed, 57.1kj of heat is released. if the experiment is repeated with 2.00mhcl(aq), how much heat would be released?

57.1 kilo Joules of heat would be released.

Explanation:

ΔH°=-57.1kJ/mol

Molarity of HCl = 2.00 M

Molarity of NaOH = 1.00 M

According to reaction , 1 M of HCl reacts with 1 M of NaOH. Then 2.00 M of HCl will react with:

of NaOH

But according to question we only have 1.00 M NaOH .So, this means that NaOH is limiting reagent and HCl is an excessive reagent.

Heat evolved will depend upon concentration of NaOH solution :

Heat evolved when 1.00 M of NaOH reacts =

Negative sign means that heat is released during the reaction.

57.1 kilo Joules of heat would be released.

the answer is c. nacl