"a freighter carrying a cargo of uranium hexafluoride sank in the english channel in late august 1984. the cargo of uranium hexafluoride weighed 2.25 x10^8 kg and was contained in 30 drums, each having a volume of 1.62 x 10^6 l. what is the density (g/ml) of uranium hexafluoride? "

4.63 g/mL is the density of uranium hexafluoride.

Explanation:

Mass of an uranium hexafluoride , m=

1 kg = 1000 g

Volume of drum in which uranium hexafluoride was stored =

1 L = 1000 mL

Volume of uranium hexafluoride stored in 30 drums = V

Density of an uranium hexafluoride =d

4.63 g/mL is the density of uranium hexafluoride.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.