The side chain (r group) of the amino acid serine is ch₂oh. the side chain of the amino acid leucine is ch₂ch(ch₃)₂. where would you expect to find these amino acids in a globular protein in aqueous solution? a) both serine and alanine would be in the interior and on the exterior of the globular protein. b) alanine would be in the interior, and serine would be on the exterior of the globular protein. c) serine would be in the interior, and alanine would be on the exterior of the globular protein. d) both serine and alanine would be in the interior of the globular protein. e) both serine and alanine would be on the exterior of the globular protein.

The answer is B, Alanine would be in the interior and serine would be on the exterior of the globular protein.

Explanation:

To further explain, the nature of solubility of side chain determines the position of the amino acid in the globular protein.

The hydrophilic amino acid such as serine are on the outside of the globular protein while the hydrophic amino acids such as leucine and alanine are on the interior of the globular protein.

This is why Alanine would be in the interior and serine would be on the exterior of the globular protein.

Cheers!

b i think it’s a water wheel turning in a stream

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.