How many grams of co₂ will be produced from 7.00 g of c₃h₈ and 98.0 g of o₂?

The answer to your question is  21 g of CO₂  

Explanation:

Balanced Reaction

                               C₃H₈  +  6O₂    ⇒    3CO₂   +   4H₂O

Data

mass of C₃H₈ = 7 g

mass of O₂  = 98 g

Determine the limiting reactant

Molecular mass of C₃H₈ = (12 x3) + (1 x 8) = 36 + 8 = 44 g

Molecular mass of Oxygen = 16 x 12 = 192 g

Theoretical proportion  C₃H₈ / O₂ = 44 / 192 = 0.23

Experimental proportion  C₃H₈ / O₂ = 7 / 98 = 0.07

As the proportion diminishes in the experiment, the excess reagent is the oxygen and the limiting reactant is propane.

- Calculate the mass of CO₂

                     44 g of C₃H₈   3(44) of CO₂

                       7 g of C₃H₈       x

                       x = (7 x 3(44)) / 44

                       x = 924 / 44

                       x = 21 g of CO₂                        

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