The radioactive isotope 32p decays by first-order kinetics and has a half-life of 14.3 days. how long does it take for 75.0% of a sample of 32p to decay?

Answer : The time passed in days is 28.6 days.

Explanation :

Half-life = 14.3 days

First we have to calculate the rate constant, we use the formula :

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

where,

k = rate constant  =

t = time passed by the sample  = ?

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process = 100 - 75.0 = 25.0 g

Now put all the given values in above equation, we get

Therefore, the time passed in days is 28.6 days.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

ljjjljlj kjlk,ljym jlyu; jm; l mumytj