Astudent isolated 16 g of a compound following a procedure
that would theoretically yield 39 g. what was his percent yield?

41.03%

Explanation:

From the question;

We are required to determine the percent yield

Thus, in this case;

% yield = (16 g ÷ 39 g)× 100

            = 41.03%

Thus, the percent yield is 41.03%

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the answers would be

the first one and the second one