If  16.8 ml  of the analyte h2c2o4  (oxalic acid) is titrated with  0.501 m  koh to  13.54 ml, determine the mass of the analyte.

Mass of Analyte H2C2O4 = 18.18 grams

Explanation:

The balanced equation is:

The Molarity of Oxalic acid needed can be determined using:

Here M1 = Molarity of Oxalic acid

V1 = Volume of oxalic acid

M2 = Molarity of KOH and V2 = Volume of KOH

M1 = ? , V1 = 16.8 mL , M2 = 0.501 M   ,  V2 = 13.54 mL

Put the values and solve for M2,

We are multiplying by 2 because , 1 H2C2O4 needs 2 KOH

Hence Molarity of H2C2O4 =

0.202 M

Molar mass = H2C2O4 = 2x1 +2x12 + 4x16

= 2+24+64 =  90 gram

18.18 gram