Which element is the reducing agent in this reaction? 2kmno4+3na2so3+h2o→2mno2+3na2so4+2k oh

oxidizing no. of Mn in(MnO4)- ion has decreased from +8 to +4

oxidizing no. of S in SO# ion has increase from 4 to 6

So MnO4 has reduced. This means that the reducing agent is the (SO3)- ion

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

hloride, what is the mass of calcium in

explanation: