A0.050 mm solution of alcl3 had an observed osmotic pressure of 3.85 atmatm at 20 ∘c . calculate the van't hoff factor iii for alcl3.

The van't Hoff factor = 3.20

Explanation:

Step 1: data given

Osmotic pressure of a 0.050 M Solution is 3.85 atm

Temperature = 20.0 °C

Step 2:

Osmotic pressure depends on the molar concentration of the solute but not on its identity.

We can calculate the osmotic pressure by:

π = i.M.R.T

 ⇒ with π = osmotic pressure = 3.85 atm

 ⇒ with i = van 't Hoff factor  = TO BE DETERMINED

 ⇒ with M = molar concentration of the solution =0.050 M

 ⇒ with R = gas constant =0.08206 L * atm / mol* K)

  ⇒ with T = Temperature of the solution =20°C = 293 K

i = π / M.R.T

i = 3.85 / 0.050*0.08206*293

i = 3.20

The theoretical Van't Hoff factor is 4:

AlCl3(aq) → Al^3+(aq) + 3Cl^-(aq)

AlCl3 dissociates in 1 mol Al^3+ + 3 moles Cl-

Due to the interionic atractions the Van't hoff factor is less than the theoretical value of 4

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

diaria maybe go see a doctor about that