Asolution is made by mixing of acetyl bromide and of heptane . calculate the mole fraction of acetyl bromide in this solution. be sure your answer has the correct number of significant digits.

The question is incomplete, here is the complete question:

A solution is made by mixing 127.g of acetyl bromide and 90.g of heptane . Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 3 significant digits.

The mole fraction of acetyl bromide is 0.534 and heptane is 0.466

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of acetyl bromide = 127. g

Molar mass of acetyl bromide = 123 g/mol

Putting values in equation 1, we get:

Given mass of heptane = 90. g

Molar mass of heptane = 100.2 g/mol

Putting values in equation 1, we get:

Mole fraction of a substance is given by:

For acetyl bromide:

For heptane:

Hence, the mole fraction of acetyl bromide is 0.534 and heptane is 0.466

answer

the ions in solute supperate from eachouthere

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.