Use the balanced equation below to determine how many grams of hno3 can be produced if we have 20.0 grams of no2.

3no2 + h2o --> 2hno3 + no

The answer to your question is  18.26 g of HNO₃

Explanation:

Data

mass of HNO₃ = ?

mass of NO₂ = 20 g

Balanced equation

                               3NO₂  + H₂O   ⇒   2HNO₃  +   NO

Checked that the equation is balanced

                        Reactants        Elements        Products

                              3                      N                       3

                              7                      O                        7

                              2                      H                       2

This equation is balanced

- Calculate the molecular mass of

  - HNO₃   = (1 x 1) + (14 x 1) + (16 x 3) =63 g

  - NO₂    = (1 x 14) + (16 x 2) = 46 g

- Use proportions to find the answer

                         3(46) g of NO₂   2(63) g of HNO₃

                         20 g    of NO₂      x

                         x = (20 x 126) / 138

                         x = 2520 / 138

                         x = 18.26 g of HNO₃

We'll have 18.27 grams of HNO3

Explanation:

Step 1: Data given

Mass of NO2 = 20.0 grams

Molar mass of NO2 = 46.01 g/mol

Step 2: The balanced equation

3NO2 + H2O → 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = mass NO / molar mass NO

Moles NO2 = 20.0 grams / 46.01 g/mol

Moles NO2 = 0.435 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 0.435 moles NO2 we'll have 2/3 * 0.435 = 0.290 moles HNO3

Step 5: Calculate mass of HNO3

Mass HNO3 = moles HNO3 * molar mass HNO3

Mass HNO3 = 0.290 moles * 63.01 g/mol

Mass HNO3 = 18.27 grams

We'll have 18.27 grams of HNO3

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b