If 1 gram of calcium chloride is dissolved in 100 ml of pure water, what temperature change will be observed

Explanation:

It is known that the molecular weight of is 111 g/mol. This means that 1 mole of contains 111 g .

      1 g =

As we know that the density of water is 1 g/cc (as 1 ml = 1 cc).

So,   100 ml water = 100 g water. Therefore, in 100 g of water present will be calculated as follows.

              mol

So, in 1000 g water the amount of present will be calculated as follows.

                  = 0.09 mol

Hence, the molality of is 0.09 mol.

According to Raoult's law,

where,   = boiling point constant

For pure 1 kg water, = 0.52 K.kg/mol

                    m = molality of solution

Therefore, putting the given values into the above formula as follows.

                          =

                          = 0.0468 K

Therefore, the boiling point will raise by 0.0468 K.