Asample of helium gas occupies 2.65 l at 1.20 atm. what pressure would this sample of gas exert in a 1.50 l container at the same temperature?

Answer : The final pressure of the gas is, 2.12 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

or,

where,

= initial pressure of gas = 1.20 atm

= final pressure of gas = ?

= initial volume of gas = 2.65 L

= final volume of gas = 1.50 L

Now put all the given values in the above equation, we get:

Therefore, the final pressure of the gas is, 2.12 atm

0.88m hope i am correct : )